how to get full url to image - function?

levista

I am playing around & modifying my zenphoto install. I am trying to find a way to get the full complete url to the images as seen in my ftp program but can't manage it.

I tried <?php echo getProtectedImageURL();?> as I saw it is used on the image.php to click through to the image alone but no success at all.

To give you an idea of what I am trying to do, I am passing the image to another php page to modify it, my current code attempt is;

`

[code]

" target="_blank">modify

[/code]

`

levista

just to clarify further, rather than this ;

`

"/gallery/zp-core/i.php?a=videogames%2Fgod+of+war&i=god+of+war.jpg&s=120"

`

i want this

`

http://www.mysite.com/gallery/videogames/godofwar/godofwar.jpg

`

jlang

`echo getMainSiteURL()."/".getFullImageURL()` will return the image as seen from the browser, as something like http://www.website.com/gallery/albums/videogames/godofwar/godofwar.jpg

Depending on your host's configuration where your website is basically mapped from a directory on another computer, your ftp program would probably look at a file location something like:
/local/home/username/www.website.com/gallery/videogames/godofwar/godofwar.jpg and I don't know how to get that one out. In fact for security it may make more sense to prevent it getting out!

junko

Hi guys,

I want something similar to this.

On `album.php`:

I have a list of thumbnails of the images, clicking one image opens it in a Colorbox lightbox, but for that to work, you need a path to the .jpg/.png, rather than a `[...]/zenphoto/pre-wedding/img_0003.jpg.php`

Thanks

sbillard

There is a function to get that url. Please look in the functions guide.

Simounet

Hi,

I also get a problem with the last version of ZP. Even if I unprotected from hotlinking, I can't get the clean URL with getFullImageURL(). Where am I wrong ?

Regards.

acrylian

Example please... Make sure you don't have the html cache enabled.

Simounet

Code:
`"><?php printImageThumb(getImageTitle()); ?>`

Result:
`...`