Print first level albums from second level albums

risk08

Hello all,
I've got album named,for example,'graphics' and subalbums 'birds' and 'fishes' in it. I need to print links to 'birds' and 'fishes' in both of them. How I can do it?

PS. Sorry for my bad english

sbillard

If you "know" the names of the albums you can make static links using the form `http://domain/zenphoto folder/graphics/birds` and `http://domain/zenphoto folder/graphics/fishes` (This assumes mod_rewrite is enabled for your site.)

If you need to discover the subalbums you can use the object model: `$mainAlbumObject->getAlbums(0);` This will return, in the case of your example, an array containing `[birds, fishes]` You create the links from there.

acrylian

You could also use the print_album_menu plugin with appropiate settings.

risk08

sbillard, thanks! I will try to use getAlbums() function.
acrylian, I tried, but I failed =\

risk08

getAlbums() gets ALL albums from gallery, i don't need it. And I don't know how to get names and etc. of that albums..
how to use print_album_menu plugin for my need?

acrylian

No, it is also a album class method which means used on an album it gets its direct subalbums.

Regarding the album menu please see the documentation.

risk08

I can't find which variable I must use, can you help me?
(now it's $_zp_current_album->getAlbums(), that's not right)

acrylian

The $_zp_current_album variable containing the object of the current album is only setup in album context. (next_album loop or on album.php). To use a specific album outside of that you have to setup the album object before hand. Please take the time to read a little on the theming tutorial and the object model tutorial.

risk08

Sorry, but English isn't my native language, so reading manuals for me is very hard. Can you just give me source?

acrylian

Sorry, our site is English only. Examples are in those tutorials.

risk08

I don't get which variable I must use

risk08

risk08

Last questions:
1. how to get album name from Album object?
2. is there any function to get name of parent album from subalbum?

acrylian

1. http://www.zenphoto.org/documentation/classes/Album.html#var$name
2. http://www.zenphoto.org/documentation/classes/Album.html#methodgetParent

You will probably also need to understand the concept of object orientation.

risk08

I made it like this:
[code]
$a=$_zp_current_album->getParent()->getAlbums();
foreach($a as $val) {
$b = new Album($_zp_gallery,$val,true);
echo "name.">".$b->data[title]."";
[/code]